设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=?
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设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x,则f(x+1)=?设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x,则f(x+1)=?设f
设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=?
设f(x)满足f(1/x)=x/1-x
设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=?
设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=?
f(1/x)=x/(1-x)=1/[(1/x)-1],
所以有f(x)=1/(x-1),且x≠0,x≠1
所以f(x+1)=1/x,且x∈(-无穷,-1)∪(-1,0)∪(0,+无穷)
f(x)=-1/x
f(1/x)=x/(1-x)=1/[(1/x)-1]
f(x)=1/(x-1)
f(x+1)=1/x
f(1/x)=x/(1-x)
得出f(x)=(1/x)/(1-(1/x))
化简得
f(x)=1/(x-1)
所以
f(x+1)=1/(x+1-1)=1/x
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