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已知0已知0请写出较完整的解答过程已知001logablogab=1/logbalogab+logba=logab+1/logab=-[-logab+1/(-logab)]当logab=1/logab
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0
logab<0,logba<0
logab=1/logba
logab+logba
=logab+1/logab
=-[-logab+1/(-logab)]
<=-2
当logab=1/logab
取等.
取值范围为(-无穷,-2]