lim x趋于π sin{2(X-π)/(X-π)}求极限lim x趋于π {sin2(X-π)/(X-π)}求极限

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limx趋于πsin{2(X-π)/(X-π)}求极限limx趋于π{sin2(X-π)/(X-π)}求极限limx趋于πsin{2(X-π)/(X-π)}求极限limx趋于π{sin2(X-π)/(

lim x趋于π sin{2(X-π)/(X-π)}求极限lim x趋于π {sin2(X-π)/(X-π)}求极限
lim x趋于π sin{2(X-π)/(X-π)}求极限
lim x趋于π {sin2(X-π)/(X-π)}求极限

lim x趋于π sin{2(X-π)/(X-π)}求极限lim x趋于π {sin2(X-π)/(X-π)}求极限
你的式子没对哦,该是如下才对
limx->π sin[2(x-π)]/(x-π)
=limx->π 2*sin[2(x-π)]/2(x-π)
=2limx->π sin[2(x-π)]/2(x-π)
=2*1
=2

这属于0/0型,所以选择用洛必达法则!
原式=lim(x→π)[sin2(x-π)]/(x-π)
=lim(x→π)2cos2(x-π)
=2cos0
=2.
但愿对你有帮助!