根号4-x^2(1+2cos^3x)dx的定积分求详解呀!

根号4-x^2(1+2cos^3x)dx的定积分求详解呀! 求定积分∫(π/2,-π/2) 根号cos^x-cos^4x dx∫(π/2,-π/2) 根号cos^2x-cos^4x dx 1/(2+sin^2x) dx cos根号下x dx 求高数大神指导 x^3根号1+x^2dx cos(x^2)dx ：求 ∫ sin^2x cos^2x dx 和 ∫ x^5根号(1-x^2) dx ∫ x^3根号1+4x^2dx过程 x-9/[(根号)x]+3 dx ∫ x+1/[(根号)x] dx ∫ [（3-x^2）]^2 dx 几道微积分题目（1）∫X^2/(根号1-X^2)dx(2)∫ln(1+X)dx(3)∫x*cos平方Xdx 求不定积分∫{ x^4 + [1/(3x)]-cos 2x } dx∫{ x^4 + [1/(3x)]-cos 2x } dx 求不定积分 3^(1/x)/x^2 dx 根号x/(根号x)-1)dx 1/(根号x^2-求不定积分 3^(1/x)/x^2 dx根号x/(根号x)-1)dx1/(根号x^2-1)dx (1-x^2)^3开根号dx ∫[1/(sin^2(x)cos^4(x)]dx 求解∫1/(cos^4(x)sin^2(x))dx ∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 请把过程写出来哈.>< 旷 这个怎恶魔算∫cos x / ( 1 + (sinx)^2 ) dx = ∫x^3 / ( 1 + x^4 ) dx = ∫(sec x)^3 * tan x dx = ∫x^2 * e^(-2x) dx = ∫x * cos 2x dx = ∫(cos 2x)^2 dx = ∫(13x - 6) / ( x (x-2)(x+3) )dx = ∫(x^2 + 2x - 2) / ((x-2)(x+1)) dx = 求不定积分(3-x)/根号(1+x+x^2)dx ∫ cos(x-1)dx、 ∫ x^3e^x^2dx怎么解