f(x)=1/(2x -1) +1/2 判断f(x)的奇偶性

f(x)满足:2f(x)-f(1/x)=x+1,求f(x) 若f(x)满足f(x)-2f(1/x)=x,则f(x)=? 若F(x)满足f(x)+2f(1/x)=x,则f(x)= 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 已知f(x)满足2f(x)+f(1/x)=3x,求f(x) F(X)满足F(x)+2f(x分之1)=3X,求f(x) 已知f(x)满足2f(x)+f(1/x)=3x,求f(x)? 已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x) 已知f(x)满足f(x)+2f(1/x)=3x,求f(x) , f(x)+f((x-1)/x)=2x; x!=0,1; 求f(x) f(x)+f[(x-1)/x]=2x x不等于0,1.求f(x). max{f(x),g(x)}=1/2(f(x)+g(x)+|f(x)-g(x)| f(x)={2x+1,x f(x)={1+x/2,x f(x)=(x-1)/(x+2) f(x-1)=2x/x-1求f(x)=?f(x+1)=? f(x+1)=f(1-x)怎么得出f(-x)=f(x+2) F(X+1)=F(-X+1)怎样得到F(X)=F(2-X)