已知α为锐角,且cos(α+π/4)=3/5,则sinα=

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已知α为锐角,且cos(α+π/4)=3/5,则sinα=已知α为锐角,且cos(α+π/4)=3/5,则sinα=已知α为锐角,且cos(α+π/4)=3/5,则sinα=解∵a是锐角即a∈(0.π

已知α为锐角,且cos(α+π/4)=3/5,则sinα=
已知α为锐角,且cos(α+π/4)=3/5,则sinα=

已知α为锐角,且cos(α+π/4)=3/5,则sinα=

∵a是锐角
即a∈(0.π/2)
∴a+π/4∈(π/4,3π/4)
∴sin(a+π/4)>0
∵cos(a+π/4)=3/5——利用sin²a+cos²a=1
∴sin(a+π/4)=4/5
∴sina
=sin[(a+π/4)-π/4]
=sin(a+π/4)cosπ/4-cos(a+π/4)sinπ/4
=√2/2(4/5-3/5)
=√2/10

cos(α+π/4)=3/5
sin(α+π/4)=4/5
sinα=sin[(a+π/4)-π/4]=(√2/2)sin(a+π/4)-(2/2)cos(a+π/4)
=(√2/2)(4/5-3/5)=√2/10

sin(a+兀/4)=4/5
原式变为cos(a+兀/4-兀/4)
cos(a+兀/4)cos(兀/4)+sin(a+兀/4)sin(兀/4)=cosa