lim n→∞ n/√(2n+1)(n+1)=

用夹逼定理求lim(n→∞)[√(n^2+n)-n]^(1/n) 用夹逼定理求lim(n→∞)√[(n^2+n)-n]^(1/n) lim x→n (√n+1-√n)*√(n+1/2)lim x n→∞ (√n+1-√n)*√(n+1/2) lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞ lim（n→∞) （(2n!/n!*n)^1/n的极限用定积分求是lim（n→∞) 1/n(2n!/n!)^1/n 不好意思 求lim n→∞ (1+2/n)^n+3 lim(n→∞)[1-(2n/n+3)] lim(n→∞)(2n-1/n+3) lim(n→∞)(sin(n+√(n^2+n)))^2lim(n→∞)(1/n!(1!+2!+…+n!)) lim n→∞ n/√(2n+1)(n+1)= 极限lim(n→∞)√(n^2-3n)/2n+1 等于多少 lim n〔√(n^2+1)-n〕当n→∞时的极限 lim(n→∞)[1/(3n+1)+1/(3n+2)+~1/(3n+n)] 求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞) lim（n→∞) 根号n+2-根号n+1/根号n+1-根号n 计算lim(n→∞)(1^n+2^n+3^n)^(1/n) lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限 lim（n→∞）(3n^3-2n+1)/n^3+n^2 快