若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.
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若x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.若x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.若x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.x
若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.
若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.
若 x+2y+3z=10,4x+3y+2z=15,则x+y+z=?.
x+2y+3z=10,4x+3y+2z=15
两式相加,得
x+2y+3z+4x+3y+2z=10+15
5x+5y+5z=25
5(x+y+z)=25
x+y+z=5
x+2y+3z+4x+3y+2z
=5x+5y+5z
=10+15
=25
x+y+z
=25/5
=5
你好!
x+2y+3z+4x+3y+2z
=5x+5y+5z
=5(x+y+z)=10+15=25
所以x+y+z=25÷5=5
希望我的回答对你有所帮助。
0.0
x+2y+3z+4x+3y+2z
=5x+5y+5z
=10+15
=25
x+y+z
=25/5
=5
x+2y+3z=10,4x+3y+2z=15
两式相加,得
x+2y+3z+4x+3y+2z=10+15
5x+5y+5z=25
5(x+y+z)=25
x+y+z=5
将上述两式相加,即得:5x+5y+5z=25
等式两边分别除以5,可得:x+y+z=5
5
x+2y+3Z=10,
4x+3y+2z=15
两式相加
5(x+y+z)=25
x+y+z=5
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
2x+z=10 x+y-z=4 3x-y-z=0
{2x+y=10 {x-y+z=4 {3x-y-z=0
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
若x+y+z=3y=2z,则x/x+y+z=?
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
x+2y+3z=10,x-y+4z=10,x+3y+2z=2
x+2y+3z=10,x-y+4z=10,x+3y+2z=2
x-y+4z=10,x+3y+2z=2,x+2y+3z=11.
x+y+z=4 2x+3y-z=6 3x+2y+2z=10
4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1
若x/2=y/3=z/4,则3x-2y+5z/x+y+z=
x+2y+3z=10,4x+3y+2z=15则x+y+z=
x+2y+3Z=10,4x+3y+2z=15,求x+y+z=