一架梯子靠在光滑的竖直墙壁上,下端放在水平的粗糙地面上,一人站在上面.A 3.6m long,5.0 kg ladder is leaned against a frictionless wall,making an angle of 25.0 degrees between the ladder and the wall.A 68.0kg person is stan
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一架梯子靠在光滑的竖直墙壁上,下端放在水平的粗糙地面上,一人站在上面.A 3.6m long,5.0 kg ladder is leaned against a frictionless wall,making an angle of 25.0 degrees between the ladder and the wall.A 68.0kg person is stan
一架梯子靠在光滑的竖直墙壁上,下端放在水平的粗糙地面上,一人站在上面.
A 3.6m long,5.0 kg ladder is leaned against a frictionless wall,making an angle of 25.0 degrees between the ladder and the wall.A 68.0kg person is standing,rather nonchalantly,2.4m up the ladder(not the vertical height).Find the minimun coefficient of static friction between the ladder and the ground for the ladder to not slip?
照抄的原题,所有已知条件都给了。
一架梯子靠在光滑的竖直墙壁上,下端放在水平的粗糙地面上,一人站在上面.A 3.6m long,5.0 kg ladder is leaned against a frictionless wall,making an angle of 25.0 degrees between the ladder and the wall.A 68.0kg person is stan
受力分析以及受力矩分析如图所示
所以有:u(G1+G2) *L1=G1*d1+G2*d2
其中L1=3.6*cos25 (m) d1=2.4*sin25 (m) d2=1.8*sin25(m) G1=68*9.8(N) G2=5*9.8(N),
计算可以得到 u=0.3