若函数f(x-1)=x(x-1),则f(x)=( ) (A)x(x-1) (B)x(x+1) (C)(x-1)(x+1) (D)(x-1)ˆ2

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若函数f(x-1)=x(x-1),则f(x)=()(A)x(x-1)(B)x(x+1)(C)(x-1)(x+1)(D)(x-1)ˆ2若函数f(x-1)=x(x-1),则f(x)=()(A)x

若函数f(x-1)=x(x-1),则f(x)=( ) (A)x(x-1) (B)x(x+1) (C)(x-1)(x+1) (D)(x-1)ˆ2
若函数f(x-1)=x(x-1),则f(x)=( ) (A)x(x-1) (B)x(x+1) (C)(x-1)(x+1) (D)(x-1)ˆ2

若函数f(x-1)=x(x-1),则f(x)=( ) (A)x(x-1) (B)x(x+1) (C)(x-1)(x+1) (D)(x-1)ˆ2
(B)x(x+1)

f(x-1)=[(x-1)+1](x-1)
所以f(x)=(x+1)x
选B

令t=x-1,则x=t+1;则f(t)=x(x-1)=(t+1)*t
然后就换成f(x)=x(x+1),选B

选B