已知cos(x-π/6)=-√3/3,则cosx+cos(x-π/3)的值.求详解

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已知cos(x-π/6)=-√3/3,则cosx+cos(x-π/3)的值.求详解已知cos(x-π/6)=-√3/3,则cosx+cos(x-π/3)的值.求详解已知cos(x-π/6)=-√3/3

已知cos(x-π/6)=-√3/3,则cosx+cos(x-π/3)的值.求详解
已知cos(x-π/6)=-√3/3,则cosx+cos(x-π/3)的值.求详解

已知cos(x-π/6)=-√3/3,则cosx+cos(x-π/3)的值.求详解