log4 2+log8 2=多少?

log4 2+log8 2=多少? log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的? 计算:(log4 3+log8 3)×log9 √2=? 已知1/2log8(a)+log4(b)=5/2,log8(b)+log4(a^2)=7,则ab= (log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?.. (log4(3)+log8(3))*log3(2) 已知已知log8(a)+log4(b^2)=5,log8(b)+log4(a^2)=7,求log4（根号下ab） 已知½log8（a）+log4（b）=5/2,log8(b)+log4(a^2)=7 求ab的值 log4 8-log8 4=? log3^4乘log4^8乘log8^m=log4^2麻烦过程写清楚一点.谢谢、 【（log4）^3+.（log8）^3】【.（log3）^2+.（log9）^2】=几啊 (log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)= 解方程log2(x)+2log4(x)+log8(x)=7 解方程log2(x)+2log4(x)+log8(x)=7 已知4^a=3 代数式log8(9)-2^(log4(3))用a表示为 (log3 2+log9 2)*(log4 3+log8 3)求值 化简(log4(3)+log8(3))(log3(2)+log9(2)) (log3^2 + log9^4)×(log4^3 + log8^3)