判断分段函数奇偶性lg[4^x/(4^x+1)] (x>0)f(x)= 0 (x=0)lg(4^x+1) (x<0)

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 00:16:48
判断分段函数奇偶性lg[4^x/(4^x+1)](x>0)f(x)=0(x=0)lg(4^x+1)(x<0)判断分段函数奇偶性lg[4^x/(4^x+1)](x>0)f(x)=0(x=0)lg(4^x

判断分段函数奇偶性lg[4^x/(4^x+1)] (x>0)f(x)= 0 (x=0)lg(4^x+1) (x<0)
判断分段函数奇偶性
lg[4^x/(4^x+1)] (x>0)
f(x)= 0 (x=0)
lg(4^x+1) (x<0)

判断分段函数奇偶性lg[4^x/(4^x+1)] (x>0)f(x)= 0 (x=0)lg(4^x+1) (x<0)
x>0时
f(-x)=lg[(4^x+1)/4^x]=-f(x)
x