2∧log2 1/4+(16/9)∧-1/3+lg20-lg2
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2∧log21/4+(16/9)∧-1/3+lg20-lg22∧log21/4+(16/9)∧-1/3+lg20-lg22∧log21/4+(16/9)∧-1/3+lg20-lg22∧log21/4+
2∧log2 1/4+(16/9)∧-1/3+lg20-lg2
2∧log2 1/4+(16/9)∧-1/3+lg20-lg2
2∧log2 1/4+(16/9)∧-1/3+lg20-lg2
2∧log2 1/4+(16/9)∧-1/2+lg20-lg2 那儿不是^1/3而是1/2
=1/4 +(9/16)^(1/2)+lg(20÷2)
=1/4+3/4+lg10
=1+1
=2
计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
4^1/2（log2^9-log2^5）的值 ,
lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) )
化简log2 1/2+log2 2/3+log2 3/4+.+log2 31/32
2∧log2 1/4+(16/9)∧-1/3+lg20-lg2
2∧log2 1/3等于多少
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
解不等式log2(4x+8)>log2(2x+1)
log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9
2^log2 1/4+(16/9)^-1/2+lg20-lg2-(log3 2)*(log2 3)+(√2-1)^lg1
解对数方程log2 (9∧x-4)=log2 (3∧x-2)+3
根号下[(log2^3)^2-4log2^3+4]+log2^(1/3)
根号下{[log2 （5)]^2-4log2(5)+4}+log2(1/5)
计算 根号下[(log2 5)^2-4log2 5+4]+log2 1/5
化简根号下[(log2^3)^2-4log2^3+4]+log2^(1/3)
log2 SQR(7/48)+log2 12 -1/2log2 42
log2 SQR(7/48)+log2 12 -1/2log2 48