lim((cosX)^3X)/(sinx^3),x趋于0,求极限

x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)是怎么通分的?x趋于0 lim sinx-tanx/x^3=lim sinx/x×(cosx-1)/(x^2×cosx)thank you lim((x+sinx)/(x-cosx))x->无穷 求lim（x-x*cosx)/(x-sinx) lim (x→3) (sinx+cosx)这个极限怎么求 请问高手 x趋近于0 lim (sinx-x*cosx)/(sinx)^3 能不能这样计算原式=lim sinx/(sinx)^3-lim (x*cosx)/(sinx)^3=lim 1/(sinx)^2-lim cosx/(sinx)^2=lim (1-cosx)/(sinx)^2=lim (x^2/2)/(x^2)=1/2,如果可以为何与利用麦克劳林公式所得 lim（x趋向无穷大）3+cosx/x Lim(x趋向无穷大) sinx平方+x/cosx平方-x 求Lim(x→0)(sinx/x)^(cosx/1-cosx) Lim,x-0,(1/sinx)*(1/x-cosx/sinx)=? 为什么lim sinx/(x-π) =lim cosx/1 lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 lim {(cosx)^(1/2)-(cosx)^(1/3)}/ (sinx)^2 x趋近于0 极限lim(2x^2+x)(sinx+cosx)/x^3-2x+1= x趋于无穷,求lim(x+3cosx)/(3x-2sinx) 求极限lim(sinx^3-x)/(cosx^2+x) x－＞无穷大 求lim(sinx^3-x)/(cosx^2+x) x－＞无穷大 lim[(1/(sinx)^2)-(cosx)^2/x^x] x接近于0答案是4/3 lim x趋于0 (sinx+x*cosx)/x=? x→∞ lim(cosx+x)/(sinx-x) 求极限?