x^2+2xsin(x-0.571)+2cos(x-0.571)=(pi-0.571)^2-2求用matlab怎么计算pi代表圆周率,

求不定积分,xsin^2x lim xsin(2/x) x→∞ ∫cos2x/(cos^2xsin^2x) e^xsin^2x的不定积分 求xsin(2x)的不定积分 y=xsin 2x,求dy lim(x->∞)[ xsin(2/x)+(cosx^2)/(x^2)] 极限lim x 趋无穷(sin5x/x-xsin(2/x)) 求积分 cos2x/cos^xsin^2x dx求积分cos2x/cos^xsin^2x dx 求lim(n→0)[sin2x/x-xsin(2/x)] lim(x→0)xsin *1/x^2 y=2xsin(2x+5)的导数 y=2xsin(2x+5)的导数是多少? 请问cos2x/(cos^2xsin^2x)怎么算? y=2xsin(2x+5)求导数! ∫1/根号xsin(3根号x+2)dx lim(x趋向0)1-x^2-e^(-x^2)/xsin^3(2x) 求极限lim(x→0){(2x-sin2x)/xsin^2x}