y=xsin 2x,求dy
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y=xsin2x,求dyy=xsin2x,求dyy=xsin2x,求dydy=(x)''sin2x+x*(sin2x)''=xsin2x+2xcos2xdy=(x)''﹙sin2x﹚dx+x(sin2x)''
y=xsin 2x,求dy
y=xsin 2x,求dy
y=xsin 2x,求dy
dy=(x)'sin2x + x* (sin2x)' =xsin2x + 2xcos2x
dy=(x)'﹙sin2x﹚dx + x(sin2x)' dx=﹙xsin2x + 2xcos2x ﹚dx
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