(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0 求y

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(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0求y(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0求y(2xsin(y/x)-

(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0 求y
(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0 求y

(2xsin(y/x)-ycos(y/x))dx+(xcos(y/x)+1)dy=0 求y
xsin(y/x)-ycos(y/x)]dx+xcos(y/x)dy=0 ②解初值 xy'-y=xtany/x,y(1)=π/2 1.令y/x=t,则方程化为(xsint-xtcost)dx+xtcostdx+