2^(log2 2012)怎样化简啊

2^(log2 2012)怎样化简啊 怎样计算（log2)^2+(log5)^2+(2*log2)*log5 【x】表示不超过实数x的最大整数,则【log2 1]+[log2 2]+[log2 3]+.+[log2 2012]等于? log2（log2∧16）怎样算? 一般地,n个相同的因数a相乘,记为a的n次方 此时 3叫做以2为底8的对数,记为log2 8 log2 4 =2 log2 16=4 log2 64 =6 观察上述3数 4、16、64之间满足怎样的关系式 log2 4 , log2 16 , log2 64 之间又满足怎样的关系 log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 log2^(4^7*2^5)+log2^6-log2^3 (log2 9)/(log2 8) = 2/3(log2 3) log2 3乘以log2 3等于2log2 log2(1+根号2+根号3）+log2（1+根号2-根号3）=中有一步是怎样来的解：log2(1+根号2+根号3）+log2（1+根号2-根号3）=log2[(1+√2+√3)(1+√2-√3)]=log2[(1+√2)²-(√3)²]=log2[2√2]=log2[2^(3/2)]=3/2这里log2[2 (log2)^2+(log5)^2+log2*log25 |[log2(x)]^2-3log2(x)+1| 化简：(log2(x/4))*(log2(x/2)) 2log2 10—log2 25=? (log2)2+log2*log50+1g25值 log2 50-2log2 5 等于多少? [log2]2+log2乘log50+log25