log2(1/2)和log2((a^2+a+1))比较大小log2(1/2)意思是以二为底的1/2的对数

log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 |[log2(x)]^2-3log2(x)+1| (log2)2+log2*log50+1g25值 log2(2X-1) log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 化简log2 1/2+log2 2/3+log2 3/4+.+log2 31/32 计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9 log2(1/2)和log2((a^2+a+1))比较大小log2(1/2)意思是以二为底的1/2的对数 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? 已知a=2,求log2 1 已知a>1且a^(lgb)=4次根号下2,求log2(ab)的最小值a^(lgb)=2^1/4,两边取以2为底的对数得:log2(a^(lgb))=log2(2^1/4),即lgblog2(a)=1/4,所以lgb=1/4log2(a),而log2(ab)=log2(a)+log2(b)=log2(a)+lgb/lg2,所以log2(ab)=log2(a)+1/4log2(a)lg2, 已知a>1 1/2log2 a与log2 (a+1)/2的大小关系是 [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 对数不等式求解 log2(a^2+1)更正，题面应为log2(a^2+1) log2 (2^x-1)·log2 [2^(x+1)-2] log2 (2^x-1)·log2 [2^(x+1)-2] log2(x-1)>2定义域log2(x-1)>2 定义域