设全集U=｛a1,a2,a3,a4,a5｝,集合A,B都是U的子集,且A∩B=｛a5｝,补集A∩B=｛a4｝,补集A∩补集B=｛a1,a2｝,则a3与A的关系,a3与B关系

已知全集U={a1,a2,a3,a4,a5},B=已知A={a1,a2,a3,a4,a5},B={a1^2,a2^2,a3^2,a4^2.a5^2},其中a1,a2,a3.a4.a5属于Z,a1 设全集U=｛a1,a2,a3,a4,a5｝,集合A,B都是U的子集,且A∩B=｛a5｝,补集A∩B=｛a4｝,补集A∩补集B=｛a1,a2｝,则a3与A的关系,a3与B关系 等差数列中a1+a2+a3+a4+a5=3,a1*a1+a2*a2+a3*a3+a4*a4+a5*a5=12求a1-a2+a3-a4+a5 设｛an}是等比数列、且a1+a2+a3=18 a2+a3+a4=-9 则a3+a4+a5= 设A=(a1,a2,a3,a4,a5),a1,a3,a5线性无关,a2=3a1-a3-a5,a4=2a1+a3+6a5,b=a1+a3,求方程组Ax=b的通解 设a1 a2 a3 a4 a5为自然数,A={a1 a2 a3 a4 a5},B={a1^ a2^ a3^ a4^a5^},且a1>a2>a3>a4>a5,并满足A交B={a1,a4},a1+a4=10,A并B 中各元素之和为256,求集合A 说明一下a1^之类的是a1的平方.应该是 a1 一道关于数学集合的难题!设a1,a2,a3,a4,a5 为自然数,A={a1,a2,a3,a4,a5},B={a1的平方,a2的平方,a3的平方,a4的平方,a5的平方},且a1 设a1,a2,a3,a4,a5为自然数,A=｛a1,a2,a3,a4,a5｝,B=｛a1²,a2²,a3²,a4²,a5²｝,且a1 设向量组（1）：a1,a2,a3; (2):a1,a2,a3,a4; (3):a1,a2,a3,a5. 已知秩(1)=秩(2)=3,秩(3)=4,求证a1,a2,a3,2a4+a5线性无关 设数列ai>0.且a1+a2+a3+a4+a5+a6+a7+a8+a9+a10=30,a1*a2*a3*a4*a5*a6*a7*a8*a9*a10 设a1,a2,a3,a4,a5,为正整数,A={a1,a2,a3,a4},B={a1²,a2²,a3²,a4²},其中a1,a2,a3,a4a4,a5属于正整数,且a1＜a2＜a3＜a4,同时A交B=｛a1,a4｝,a1+a4=10,当A并B元素之和为124,求集合A. 等差数列 A1+A2+A3=6,A2+A3+A4=7,A3+A4+A5= 设a1,a2,a3,a4,a5,为正整数,A={a1,a2,a3,a4,a5},B={a1²,a2²,a3²,a4²,a5²},且a1＜a2＜a3＜+＜a5,并满足A∩B={a1,a4},且a1+a4=10.求a1和a4的值,若A∪B 中各元素之和为256,求集合A.a1＜a2＜a3＜a4＜a5 设向量组 a1 a2 a3 a4 a5 线性无关,证,a1+a2,a2+a3,a3+a4,a4+a5也线性无关. 已知A={a1,a2,a3,a4,a5},B={a1^2,a2^2,a3^2,a4^2,a5^2},ai属于N*,i=1,2,3,4,5,设a1＜a2＜a3＜a4＜a5,且A∩B={a1,a4},a1+a4=10,又AUB元素之和为224,求a1,a4,a5及集合A 设集合A=﹛a1,a2,a3,a4,a5｝,B=｛a1²,a2²,a3²,a4²,a5²｝.设集合A=﹛a1,a2,a3,a4,a5｝,B=｛a1²,a2²,a3²,a4²,a5²｝,其中ai（1≤i≤5,i∈N）都是正整数,且a1＜a2＜a3＜a4＜a5,a1+a4=10, 等差数列{an}中,若a1+a3+a5=-1,则a1+a2+a3+a4+a5=? a5-a1=15,a4-a2=6,求a3