复数z^3=-10+9√3i求z+z共轭

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复数z^3=-10+9√3i求z+z共轭复数z^3=-10+9√3i求z+z共轭复数z^3=-10+9√3i求z+z共轭设Z=A+BI,所以Z^3=A^3+3A^2BI+3AB^2I^2+B^3I^3

复数z^3=-10+9√3i求z+z共轭
复数z^3=-10+9√3i
求z+z共轭

复数z^3=-10+9√3i求z+z共轭
设Z=A+BI,所以Z^3=A^3+3A^2BI+3AB^2I^2+B^3I^3
所以A^3-3AB^2=-10
3AB-B^3=9√3i
所以a=2
b=√3
剩下自行解决~