设y=[cos (1/x)]^3,则dy＝如题………………
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/18 15:44:41
设y=[cos(1/x)]^3,则dy＝如题………………设y=[cos(1/x)]^3,则dy＝如题………………设y=[cos(1/x)]^3,则dy＝如题………………y''=3[cos(1/x)]^2
设y=[cos (1/x)]^3,则dy＝如题………………
设y=[cos (1/x)]^3,则dy＝
如题………………
设y=[cos (1/x)]^3,则dy＝如题………………
y'=3[cos(1/x)]^2*[cos(1/x)]'
..=3[cos(1/x)]^2*[-sin(1/x)]*(1/x)'
..=3[cos(1/x)]^2*[-sin(1/x)]*(-1/x^2)
..=3[cos(1/x)]^2[sin(1/x)]/x^2
所以dy=3[cos(1/x)]^2[sin(1/x)]/x^2 dx
结果如下：
[3/(x^2)]*[cos(1/x)]^2*sin(1/x)dx
dy=3[cos(1/x)]^2*[-sin(1/x)]*(-1)x^(-2)
=-3[cos(1/x)]^2*[-sin(1/x)]*x^(-2)
(3*cos(1/x)^2*sin(1/x)/x^2)dx
dy=3[cos(1/x)]^2*[sin(1/x)]/x^2 dx
设y=e^(-x) cos 1/x,求dy.
设y=ln[cos(1+3x^2)],则dy=
设y=cos(2-5x) 则dy=?
设y=cos^2(x+1),求dy
设y=e^cos^2*1/x,求dy
设函数y=sin(1+x),则dy=cos(1+x)dx 对么
设y=e负X的次方cos(3-x)则dy=
设函数y=cos (x+1)/2 ,则dy=
设y=[cos (1/x)]^3,则dy＝如题………………
设y=cos(x^2+e^x)求dy
设函数y=x3 cos x ,求dy
设y=e^cos^21/x,求dy
dy/dx=1-cos(y-x)
设y=e^(-x)cos(3-x),求dy 详细些
设y=3^x+cos^5x,求dy需要具体步骤
设y=(根号1+x^2)+cos^2x,dy
设y=cos(2x^2+x+1) 求dy/dx. 过程
已知函数y=cos(3x),则dy=?