Y=sin^2x+sin2x+2cos^2x化简
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 16:38:44
Y=sin^2x+sin2x+2cos^2x化简Y=sin^2x+sin2x+2cos^2x化简Y=sin^2x+sin2x+2cos^2x化简y=sin²x+sin(2x)+2cos
Y=sin^2x+sin2x+2cos^2x化简
Y=sin^2x+sin2x+2cos^2x化简
Y=sin^2x+sin2x+2cos^2x化简
y=sin²x+sin(2x)+2cos²x
y=sin²x+2sinx·cosx+2cos²x
y=(sinx+cosx)²+cos²x
好像只能化简到这里了
—(sinx-cosx)^
Y=sin^2x+sin2x+2cos^2x
=(1-cos2x)/2+sin2x+1+cos2x
=3/2+1/2cos2x+sin2x
=3/2+根号5/2*sin(2x+v),其中cosv=根号5/5,sinv=2根号5/5
y=根号2sin2x变换到sin^2x+sin2x+2cos^2x
证明tan(x+y)+tan(x-y)=sin2x/cos^2x-sin^2y
证明sin2x+sin2y=2sin(x+y)cos(x-y)怎么做
sin2x+sin2y=2sin(x+y)cos(x-y) 怎么算?
sin2x+sin2y=2sin(x+y)cos(x-y)怎么得的
y=sin^2x-3sinxcosx+4cos^2x是否等于y=sin^2x+cos^2x+3cos^2x-3/2*sin2x?y=sin^2x-3sinxcosx+4cos^2xy=sin^2x+cos^2x+3cos^2x-3/2*sin2x=1+3cos^2x-3/2*sin2x=1+3(1-sin^2x)-3/2*sin2x=-3sin^2x-3/2*sin2x+4
Y=sin^2x+sin2x+2cos^2x化简
y=3sin^2x-2sin2x+11cos^x的最大值
证明 2sin(π+x)cos(π-x)=sin2x
求y=(sin3x*sin^3x+cos3x*cos^3x)/cos^2x+sin2x最小值求y=(sin3x*sin³x+cos3x*cos³x)/cos²2x+sin2x最小值
求函数Y=sin^4x +cos^4x +sin^2x cos^2x 除以2-sin2x的最小正周期,最大值最小值
y=sin^2x+sin2x+2cos^x求函数的最小值 汗……不好意思,打错了是y==sin^2x+sin2x+2cos^2x
若x属于(0,π/2)则函数y=(2sin^2 x+cos^2 x)/sin2x的最小值为?分母为sin2x 不是sinx平方~
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
化简:sin2x+sin(π-x)/2cos2x+2sin^2x+cos(-x)=?
已知函数y=sin^2x+sin2x+3cos^2x,求函数的最小值和单调减区间
求函数y=[sin2x+sin(2x+π/3)]/[cos2x +cos(2x+π/3)]的最小正周期
若函数y=cos^2 x - sin^2 x - √3sin2x+1求最大最小值.和最小周期