求lim(x->0)x^2*sin(1/x)/sinx,我算是sin(1/x)～1/x,sinx～x,那么lim(x->0)x^2*sin(1/x)/sinx=lim(x->0)x^2*(1/x)/x=x/x=1为什么用夹逼定理求极限却等于0

求极限lim(x-->0)x^2 sin(1/x), 求极限 lim sin(x^2 * sin (1/x))/x x->0求极限 lim sin(x^2 * sin (1/x))/x x->0 lim x->0(sqrt(sin(1/x^2)) 求极限 求极限 （（sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1 求极限,lim x趋于0 x * sin 1/x 求极限：lim(x*sin(1/x))^2 求极限ln(1+2x)/sin(1+2x),lim x->0求它极限. lim(x趋向0)ln(1+sin x)/x^2 求 lim(x→1)sin(x+1)/x+1 求 lim(x→2)x²-4/x-2 lim(x(sin)^2) 求极限lim(x趋向于0)ln(1+x^2)/sin(1+x^2) 求极限：lim x→0 ln[1+sin^2(x)]/[e^(x^2)－1] 求lim(x-0)1-cos4x/2sin^2x+xtan^2x的极限 lim 1-cos4x/2sin^2x+xtan^2x x趋近于0 求极限 求极限lim(x→0) sin(1-x)/(1-x^2) 求极限 lim(x→0){x[sin(1/x^2)-1/sin2x]} lim x→0 (x∧2 cscx sin(1/x)) 求极限 求极限 ln (1+2x)/sin x,lim x->0 请用洛必达法则求解,