lim(x→0)(cos x)∧(1/sin 2x)＝?
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lim(x→0)(cosx)∧(1/sin2x)＝?lim(x→0)(cosx)∧(1/sin2x)＝?lim(x→0)(cosx)∧(1/sin2x)＝?f(x)=(cosx)^(1/sin2x),
lim(x→0)(cos x)∧(1/sin 2x)＝?
lim(x→0)(cos x)∧(1/sin 2x)＝?
lim(x→0)(cos x)∧(1/sin 2x)＝?
f(x) = (cos x)^(1/sin 2x),lnf(x) = 1/(sin2x) ln cosx = ln(cosx) / sin2x
lim(x->0) lnf(x)
= lim(x->0) ln(cosx) / sin2x ln(1 + cosx-1) cosx -1
= lim(x->0) (cosx -1) / (2x) cosx -1 -x²/2
= lim(x->0) (-x²/2) / (2x )
= 0
原式 = e^0 = 1
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