log2(x+1/(x-1)+5)(x>1)的最小值是多少?

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log2(x+1/(x-1)+5)(x>1)的最小值是多少?log2(x+1/(x-1)+5)(x>1)的最小值是多少?log2(x+1/(x-1)+5)(x>1)的最小值是多少?令y=x+1/(x-

log2(x+1/(x-1)+5)(x>1)的最小值是多少?
log2(x+1/(x-1)+5)(x>1)的最小值是多少?

log2(x+1/(x-1)+5)(x>1)的最小值是多少?
令y=x+1/(x-1)+5
=(x-1)+1/(x-1)+6
因为x>1,所以x-1>0
所以,y>=2根号[(x-1)/(x-1)]+6=8
所以log2(y)>=log2(8)=3