log2 (8-e^cosπ/2)=( )求详解,
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log2(8-e^cosπ/2)=()求详解,log2(8-e^cosπ/2)=()求详解,log2(8-e^cosπ/2)=()求详解,cosπ/2=0e^0=1∴log2(8-e^cosπ/2)=
log2 (8-e^cosπ/2)=( )求详解,
log2 (8-e^cosπ/2)=( )求详解,
log2 (8-e^cosπ/2)=( )求详解,
cosπ/2
=0
e^0=1
∴
log2 (8-e^cosπ/2)
=log2(8-1)
=log2(7)
感觉题目不是这样的
log2 (8-e^cosπ/2)
=log2 (8-e^o)
=log2 (8-1)
=log2 (7)
log2 (8-e^cosπ/2)=( )求详解,
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