函数y=2sinxcosx-2sin²x+1的值域=?
来源：学生作业帮助网 编辑：六六作业网 时间：2025/01/23 10:36:59
函数y=2sinxcosx-2sin²x+1的值域=?函数y=2sinxcosx-2sin²x+1的值域=?函数y=2sinxcosx-2sin²x+1的值域=?y=2s
函数y=2sinxcosx-2sin²x+1的值域=?
函数y=2sinxcosx-2sin²x+1的值域=?
函数y=2sinxcosx-2sin²x+1的值域=?
y=2sinxcosx-2sin²x+1
=sin2x-(2sin²x-1)
=sinn2x-(-cos2x)
=sin2x+cos2x
=√2sin(2x+π/4)
值域为 [-√2,√2]
y=2sinxcosx-2sin^2x+1
=2sinxcosx+1-2sin^2x
=sin2x+cos2x
=√2(√2/2sin2x+√2/2cos2x)
=√2(sin2xcosπ/4+cos2xsinπ/4)
=√2sin(2x+π/4)
-1<=sin(2x+π/4)<=1
-√2<=√2sin(2x+π/4)<=√2
所...
全部展开
y=2sinxcosx-2sin^2x+1
=2sinxcosx+1-2sin^2x
=sin2x+cos2x
=√2(√2/2sin2x+√2/2cos2x)
=√2(sin2xcosπ/4+cos2xsinπ/4)
=√2sin(2x+π/4)
-1<=sin(2x+π/4)<=1
-√2<=√2sin(2x+π/4)<=√2
所以y=2sinxcosx-2sin^2x+1的值域：[-√2，√2]
y=2sin^2 X + 2sinxcosx-1 = 1 - cos 2x + sin 2x - 1 = sin 2x - cos 2x = sin (2x - 45°)最小正周期：2π/2 = π
收起
函数y=sinxcosx-3sin^2(x)的最大值
已知函数Y=2sin^X+2sinXcosX-5cos^X 已知函数Y=2sin^X+2sinXcosX-5cos^X,帮我化简
已知函数y=cos²x-sin²x+2sinxcosx,求函数值域
已知函数y=sin²x+sinxcosx+2(x∈R),求函数的值域
函数y=cos^2x-sin^2x+2sinxcosx的最小值是?
函数y=cos＾2x-2sinxcosx-sin＾2x的值域是多少
函数y=2sinxcosx-2sin^2x+1的最小正周期是
求函数y=2sin^2x+sinxcosx-cos^2x值域
函数y=2sinxcosx+1-2sin^2x的最小正周期是
函数y=1-2sin*2x+2sinxcosx'求最小正周期'值域
求函数y=2sin²x+2根号3 sinxcosx-2的周期
函数y=2sinxcosx－2sin^2x+1的最小正周期是多少?
函数y=2sinxcosx-2sin²x+1的值域=?
函数y=1/2sin(2x + pai/3)-sinxcosx的单调递减区间?
函数Y=sinXcosX(sin^2X-cos^2X)的最小值
函数y=sin^2x-sinxcosx-cos^2x的最小值
函数y=1/2sin(2X+TT/3)-sinXcosX的单调递减区间是
已知函数y=sin^2x+sinxcosx+2,(x属于R),求值域