lim(x→-1)x^2-1/x^3-1=
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lim(x→-1)x^2-1/x^3-1=lim(x→-1)x^2-1/x^3-1=lim(x→-1)x^2-1/x^3-1=错了吧,应该是x→1这样则原式=(x+1)(x-1)/(x-1)(x&su
lim(x→-1)x^2-1/x^3-1=
lim(x→-1)x^2-1/x^3-1=
lim(x→-1)x^2-1/x^3-1=
错了吧,应该是x→1
这样则原式=(x+1)(x-1)/(x-1)(x²+x+1)
=(x+1)/(x²+x+1)
x→1
所以极限=(1+1)/(1+1+1)=2/3
如果确实是x→-1
则极限=(1-1)/(-1-1)=0
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