2[2sin(x+π/6)×cosx]化简得?

2[2sin(x+π/6)×cosx]化简得? 利用cosx=sin(π/2-x),sin'x=cosx,证明(cosx)'=-sinx 2[sin(x+π/6)×cosx] 等于多少? sin(x-π/6）cosx 怎么化简为1/2sin(2x-π/6)-1/4 化简(sin^2 x/sin x-cosx)-(sin x+cosx/tan^2 x-1) sin(x+1/2π)=cosx?还是cos-x 为什么 f(x)=sin(x+π/2)=cosx 已知函数f(x)=2sinxcos(π/2-x)-根号3sin(π+x)cosx+sin(π/2+x)cosx怎么化简. f(x)=sin(x+π/6)+sin(x-π/6)+cosx+af(x)=2sinxcos(π/6)+cosx+a用的是什么公式? (sin^x/sinx-cosx)-sinx+cosx/tan^2x-1 y=sin(x+π/6)+sin(x-π/6)+cosx ,x∈[-π/2,π/2]的值域 化简变形f(x)=[2sin(x+π/3)+sinx]cosx-√3sin^2x 若x属于(0,π/2),且6 cosx=5 tan X,则sin X 2sina(x-π/4)sin(x+π/4) 怎么转换成(sinx-cosx)(sinx+cosx)? sin^2x根号下(1+cosx)/(1-cosx) 证明x∈(0,π/2),cos(cosx)>sin(sinx) 求证sinx-cosx=根号2sin(x-π/4) sinx：sin(x/2)＝6：5 求cosx