f(x+1)=x^2-2x-1,求f(x)
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f(x+1)=x^2-2x-1,求f(x)f(x+1)=x^2-2x-1,求f(x)f(x+1)=x^2-2x-1,求f(x)f(x+1)=x^2-2x-1=(x+1)^2-4(x+1)+2,f(x)
f(x+1)=x^2-2x-1,求f(x)
f(x+1)=x^2-2x-1,求f(x)
f(x+1)=x^2-2x-1,求f(x)
f(x+1)=x^2-2x-1=(x+1)^2-4(x+1)+2 ,f(x)=x^2-4x+2
f(x+1) = (x+1-2)^2-2
=>f(t) = (t-2)^2-2
f(x) = (x-2)^2-2
f(x+1)=x²-2x-1
f(x+1)=(x²+2x+1)-4x-2
f(x+1)=(x+1)²-4x-4+2
f(x+1)=(x+1)²-4(x +1)+2
所以，f(x)=x²-4x+2
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