y=tan(x+y)二阶导数

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y=tan(x+y)二阶导数y=tan(x+y)二阶导数y=tan(x+y)二阶导数y''=dy/dx=sec^2(x+y)·(1+y'');→[sec^2(x+y)-1]·y''=sec^2(x+y);→

y=tan(x+y)二阶导数
y=tan(x+y)二阶导数

y=tan(x+y)二阶导数
y'= dy/dx =sec^2(x+y)·(1+y');
→[sec^2(x+y) -1]·y'=sec^2(x+y);
→[tan^2(x+y) ]·y'=sec^2(x+y);
→y'=1/sin^2(x+y);
则:
y'' =dy' /dx
=d[sin^(-2)(x+y)] /dx
=(-2)·sin^(-3)(x+y) ·cos(x+y)·(1+y')
=-2·sin^(-3)(x+y) ·cos(x+y)·[1+sin^(-2)(x+y)]
=-2·cos(x+y)·[sin^(-3)(x+y) +sin^(-5)(x+y)]

y=tan(x+y)
两边同时对x进行求导:y'=sec²(x+y)×(1+y')
[1-sec²(x+y)]y'=sec²(x+y)
-tan²(x+y)y'=sec²(x+y)
...

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y=tan(x+y)
两边同时对x进行求导:y'=sec²(x+y)×(1+y')
[1-sec²(x+y)]y'=sec²(x+y)
-tan²(x+y)y'=sec²(x+y)
y'=-1/sin²(x+y)
两边同时对x进行求导:y''=-2×[sin(x+y)]^(-3)×cos(x+y)×(1+y')
=-2×[sin(x+y)]^(-3)×cos(x+y)×[1-1/sin²(x+y)]
=2cos³(x+y)/[sin(x+y)]^5

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