x+1/5x=120

证明(x+1)(X+3)(x+5)(x+7)+15=(X+8x)+22(x+8x)+120 x.x-5x+1=0,那么x.x+1/x.x 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) x(x-2)-2x(x+1)-3x(x-5) 其中x=负½ (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x x(x+1)(x-1)=120 f(x,-x)=x^2+2x,fx(x,-x)=5x+1,则fy(x,-x)= x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? 提取公因式:已知x*x-5x+1=0 求x*x*x-4x*x-4x-1 已知3x*x-x=1,求6x*x*x+7x*x-5x+2000 x+2/3x=60 x-3/5x=120 4x+18x=1x+2/3x=60 x-3/5x=120 4x+18x=132! x+1=5x,x= 写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4 x+1/5x=120 100-2x+5x=120(x+3)×5-2x=30100-(4x+1)-(4x+1)=204x+8=6x-10 100-2x+5x=120(x+3)×5-2x=30100-(4x+1)-(4x+1)=204x+8=6x-10 证明(x+1)(x+3)(x+5)(x+7)+15=(x^2+8x)^2+22(x^2+8x)+120