设z=f(x,y)满足dz=(x2y-2)dx(xy²-2)dy

设Z=f(x^2+y,2xy),求dz/dx和dz/dy设Z=f(x^2+y,2xy),求dz/dx和dz/dy设Z=f(x^2+y,2xy),求dz/dx和dz/dyu=x^2+y∂u/

设z=f(x+y),则dz=设z=f(x+y),则dz=设z=f(x+y),则dz=dz=f''dx+f''dy

设z=x^y,求dz设z=x^y,求dz设z=x^y,求dzdz=d(x^y)=d(e^(ylnx))=e^(ylnx)*d(ylnx)=x^y*(lnxdy+dy/x)=x^y*lnx*dy+x^(

设Z=f(xz,z/y)确定Z为x,y的函数求dz设Z=f(xz,z/y)确定Z为x,y的函数求dz设Z=f(xz,z/y)确定Z为x,y的函数求dzf对第1个变量的偏导函数记作f1,第2个变量的偏导

设z=f(2x+3y,e^xy),求dz设z=f(2x+3y,e^xy),求dz设z=f(2x+3y,e^xy),求dz令u=2x+3y,v=e^xydz=[2(f''u)+y(e^xy)(f''v)]d

设z=(x+2y)e^xy,求dz设z=(x+2y)e^xy,求dz设z=(x+2y)e^xy,求dzdZ　＝　эZ＆＃47；эx　＊dx　＋　эz＆＃47；эy＊dy　　　　　　　　　　　　　　＝　

设函数Z=y^(2x),求dz.设函数Z=y^(2x),求dz.设函数Z=y^(2x),求dz.Z=y^(2x)两边同取对数得：lnz=2xlny再分别求导：(1/z)dz=2dxlny+2x(1/y

设f(u,n)具有连续的二阶偏导数,z=f(3x+2y,y²),求2z/2x+2²z/2x2y设f(u,n)具有连续的二阶偏导数,z=f(3x+2y,y²),求2z/2x

设f(x+y,x-y)=xy,z=(xy,x/y),则dz=设f(x+y,x-y)=xy,z=(xy,x/y),则dz=设f(x+y,x-y)=xy,z=(xy,x/y),则dz=f(x,y)=(1/

设f(u,v)可微,z=f(x^y,y^x),则dz=设f(u,v)可微,z=f(x^y,y^x),则dz=设f(u,v)可微,z=f(x^y,y^x),则dz=zx=f1y*x^(y-1)+f2ln

设z=ln(x^z×y^x),求dz设z=ln(x^z×y^x),求dz设z=ln(x^z×y^x),求dzz=lnx^z+lny^x=zlnx+xlnyz=xlny/(1-lnx)先关于x求偏导,把

设z=f(x,y)由方程z+x+y=e^(z+x+y)所确定,求Dz设z=f(x,y)由方程z+x+y=e^(z+x+y)所确定,求Dz设z=f(x,y)由方程z+x+y=e^(z+x+y)所确定,求

设z=f(x,y)=arctanx/y,y=√(x^2+1),求dz/dx设z=f(x,y)=arctanx/y,y=√(x^2+1),求dz/dx设z=f(x,y)=arctanx/y,y=√(x^

设z=(x+y)/(x-y),求dz设z=(x+y)/(x-y),求dz设z=(x+y)/(x-y),求dzf(x)=z=x+y/x-ydz=fxdx+fydy=[[(x-y)-(x+y)]/(x-y

【微积分】设z=z(x,y)满足方程组f(x,y,z,t)=0,g(x,y,z,t)=0,其中f,g具有连续的偏导数,求dz.【微积分】设z=z(x,y)满足方程组f(x,y,z,t)=0,g(x,y

设z=f(x/y)且f为可微函数,则dz=设z=f(x/y)且f为可微函数,则dz=设z=f(x/y)且f为可微函数,则dz=dz=f''x(x/y)dx+f''y(x/y)dy=[f''(x/y)/y]d

设z=f（x,y）由z+x+y-（e∧x+y+z）+2=0求dz设z=f（x,y）由z+x+y-（e∧x+y+z）+2=0求dz设z=f（x,y）由z+x+y-（e∧x+y+z）+2=0求dzz+x+

设z=f(y/x)且f是可微函数,求全微分dz设z=f(y/x)且f是可微函数,求全微分dz设z=f(y/x)且f是可微函数,求全微分dz我用z_x表示z对x的偏导数,其他类似：dz=z_xdx+z_

设z=f（x／y）且f是可微函数,求全微分dz设z=f（x／y）且f是可微函数,求全微分dz设z=f（x／y）且f是可微函数,求全微分dz记u=x/y,则z=f(u)u''x=1/y,u''y=-x/y^

设z=f(x/y),且f可微,求dz设z=f(x/y),且f可微,求dz设z=f(x/y),且f可微,求dzdz=δf/δxdx+δf/δydy=f`(x/y)/y*dx+f`(x/y)*(-x/y&