躯y=f(x)Ƕ0ϵļ

f(x+y)=f(x)*f(y)x>0f(x)f(x+y)=f(x)*f(y)x>0f(x)f(x+y)=f(x)*f(y)x>0f(x)令y=0,f(x+0)=f(x)*f(0)=>f(0)=1令y

恒有f(x+y)=f(x)+f(y),若x>0时,f(x)恒有f(x+y)=f(x)+f(y),若x>0时,f(x)恒有f(x+y)=f(x)+f(y),若x>0时,f(x)x=y=0f(0)=2f(

f(x+y)=f(x)*f(y)x>0f(x)f(x+y)=f(x)*f(y)x>0f(x)f(x+y)=f(x)*f(y)x>0f(x)f(x)恒等于0或者f(x)严格单调下降.对于任意的x>0,有

数学题f(X)对一切xy都有f(x+y)=f(x)+f(y)f(X)对一切xy都有f(x+y)=f(x)+f(y)且x>0时,f(x)数学题f(X)对一切xy都有f(x+y)=f(x)+f(y)f(X

已知f(x+y)=f(x)+f(y)+xY(x+y),f’(0)=1.求f(x).已知f(x+y)=f(x)+f(y)+xY(x+y),f’(0)=1.求f(x).已知f(x+y)=f(x)+f(y)

"F(x,y)=0"F(x,y)=0"F(x,y)=0一个二元函数F(x,y)它的值是0

x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0,f(x)x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0,f(x)x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0

x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0,f(x)x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0,f(x)x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0

x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0,f(x)x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0,f(x)x,y属于R且f(x)+f(y)=f(x+y)恒成立当x>0

f(x,y)=e^-y,0f(x,y)=e^-y,0f(x,y)=e^-y,0利用分布函数的关系求出概率密度的关系.这是题目分类为电脑网络,差得太远.建议你提问时以“概率”开头,更容易被分到数学类中,

导数：f(x+y)=f(x)f(y),且f''(o)=1,求f''(x)f(x+y)=f(x)f(y),且f''(o)=1,求f''(x)f(x+y)=f(x)+f(y)+2xy,且f''(o)存在,求f''(x

f(x+y)+f(x-y)=2f(x)f(y)求证：f(0)=1f(x+y)+f(x-y)=2f(x)f(y)求证：f(0)=1f(x+y)+f(x-y)=2f(x)f(y)求证：f(0)=1令x=y

f(x+y)=f(x)-f(y),那么f(-x)=f(0)-f(-x)=-f(-x).2f(-x)=0?f(x+y)=f(x)-f(y),那么f(-x)=f(0)-f(-x)=-f(-x).2f(-x

已知：f(x+y)+f(x-y)=2f(x)*f(y),x.y取任何实数且f(0)不等于0,求证：f(x)为偶函数已知：f(x+y)+f(x-y)=2f(x)*f(y),x.y取任何实数且f(0)不等

(X,Y)f(x,y)={12y^2,0(X,Y)f(x,y)={12y^2,0(X,Y)f(x,y)={12y^2,0同学,我能写的就是这么多了.

已知函数f(x)满足f(x+y)+f(x-y)=2f(x)×f（y）,且f(0)≠0,证明f(x)是偶函数已知函数f(x)满足f(x+y)+f(x-y)=2f(x)×f（y）,且f(0)≠0,证明f(

已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)已知f(0)=1,f(x-y)=f(x)-y(2x-y+

已知f(x+y)=f(x)乘以f(y),且f(x)不等于0,证明f(x)>0已知f(x+y)=f(x)乘以f(y),且f(x)不等于0,证明f(x)>0已知f(x+y)=f(x)乘以f(y),且f(x

已知f(x+y)=f(x)f(y)且f(x)不等于0证明f(x)>0恒成立已知f(x+y)=f(x)f(y)且f(x)不等于0证明f(x)>0恒成立已知f(x+y)=f(x)f(y)且f(x)不等于0

f(x+y)=f(x)+f(y),f(-3)=a,如果x>0,f(x)f(x+y)=f(x)+f(y),f(-3)=a,如果x>0,f(x)f(x+y)=f(x)+f(y),f(-3)=a,如果x>0