已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)
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已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)已知f(0)=1,f(x-y)=f(x)-y(2x-y+
已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)
已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)
已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)
f(0)=f(x-x)=f(x)-x(2x-x+1)=1
f(x)=x^2+x+1
令x=0,则f(-y)=1-y(-y+1),化简下用x代替-y得，f(x)=x^2+x+1
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已知f(0)=1,f(x-y)=f(x)-y(2x-y+1),求f(x)
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