·若tan(π/4-α)=3,则cotα等于

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 00:18:46
·若tan(π/4-α)=3,则cotα等于·若tan(π/4-α)=3,则cotα等于·若tan(π/4-α)=3,则cotα等于tan-α=tan[(π|4-α)-π|4]=[tan(π|4-α)

·若tan(π/4-α)=3,则cotα等于
·若tan(π/4-α)=3,则cotα等于

·若tan(π/4-α)=3,则cotα等于
tan-α=tan[(π|4-α)-π|4]=[tan(π|4-α)-tan(π|4)]/1+tan(π|4-α)
=1/2
所以tanα=-1/2
cotα等于1/tanα=-2

tan(π/4-α)
=(tanπ/4-tanα)/(1+tanπ/4tanα)
=(1-tanα)/(1+tanα)=3
1-tanα=3+3tanα
tanα=-1/2
所以cotα=1/tanα=-2


tan(π/4-α)
=(tanπ/4-tanα)/(1+tanπ/4tanα)
=(1-tanα)/(1+tanα)=3
1+tanα不等于0

1-tanα=3+3tanα
tanα=-1/2
所以
cotα=1/tanα=-2