lim[(√2x-1)-3]/(√x-2-√2) x趋于4,怎么求lim[(√2x+1)-3]/(√x-2-√2)这个才是原式，上面的打错了

lim x-无穷 (√3x^2+1)/x+1 1、lim(x->无穷大) e^x arctanx2、lim(x->0)sinx√1+sin(1/x)3、lim(x->无穷大)【（√x^2+x+1）-【(√x^2-x+1)】4、lim(x->无穷大)((x+{x+(x)^0.5]^0.5}^0.5)/(2x+1)^0.55、lim(x->0)(sin3x+x^2sin1/x)/((1+cosx)x)6、lim(n->无穷大)(2^n)(si lim((√1+x^2)+x)/((√x^3+x)-x)x→+无穷大 1.lim x→0 3x/(sinx-x)2.lim x→0 (1-cosmx)/x^23.lim x→0 sin4x/[(√x+2)-√2]4.lim h →0 [sin(x+h)-sin(x-h)]/h 数学极限lim(x→0)((x^3)/(3*x^2-1)) lim(x→+无穷)(√x(x+2)-√(x^2-x+1)) lim(x→1)(tan(x-1))/(x^2-1) 求lim√(3-x)-√(1+x)/(x^2+x-2) (x->1) 求lim√(3-x)-√(1+x)/(x^2+x-2) (x->1) lim √（3-x）-√（1+x）/x平方+x-2x→1 lim(x趋向无穷)-(x+1)+√(x^2+1) 求lim(√x^2+1)-x x→-∞ lim(x趋于0) (√(x^2+1)-1)/x,lim(x->0) (√(x^2+1)-1)/x lim（x→1）√3-x-√1+x/x∧2-1 lim (√(x^2+1)+2x)^2/(3x^2+1) x→＋∞ 求极限lim(x->1)(√(x^2+3x)-2)/(1-x^2) lim 3次√(x^3-5x^2+1)-x X→无穷 x趋向无穷大时求lim√(x^2-3x+1)/x极限 lim x(√(9x^2+1) - 3x ) x趋于正无穷 计算极限① lim(x→+∞) 1 / [ (√x^2+3x) - x ],② lim(x→1) (sinx-sin1)/(x-1)