∫(x^1/2)sin(x^1/2)dx二楼写的详细点,三楼做错拉

∫sin^2x/(1+sin^2x )dx求解, ∫(1-sin^2( x/2))dx ∫(cosx／1+sin^2x)dx ∫sin^2x(1+tanx)dx ∫1/sin(x/2)dx ∫1+sin^2x/1-cos2x dx∫1+sin^2x/1-cos2x dx ∫1/x^2 * sin 1/x dx ∫(1+sin^2x)/(cos^2x)dx ∫e^(-2x)sin(1/2x)dx 求∫1／tan^2x+sin^2x dx ∫[1/(sin^2(x)cos^4(x)]dx ∫1-sin2x/sin^2x-x dx求不定积分 求解∫1/(cos^4(x)sin^2(x))dx ∫sin(1/x)dx ∫3/(x*x*x+1)dx ∫1/(2+sin x)dx 和 ∫1/(2sin x-cos x+5)dx的解法 sin(x^1/2)dx 求不定积分 求积分 sin(x^1/2) dx cosx/√1+sin^2x dx