化简sin^x*tanx+cos^x*1/tanx+2sinx*cosx
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化简sin^x*tanx+cos^x*1/tanx+2sinx*cosx化简sin^x*tanx+cos^x*1/tanx+2sinx*cosx化简sin^x*tanx+cos^x*1/tanx+2s
化简sin^x*tanx+cos^x*1/tanx+2sinx*cosx
化简sin^x*tanx+cos^x*1/tanx+2sinx*cosx
化简sin^x*tanx+cos^x*1/tanx+2sinx*cosx
sin^x*tanx+cos^x*1/tanx+2sinx*cosx
=(sin^x*tan^x +cos^x)/tanx +2sinxcosx
=[(sinx)^4+(cosx)^4]/[(cos^x*tanx] + 2sinxcosx
=[(sin^x+cos^x)^2-2sin^x*cos^x]/(sinxcosx) +2sinxcosx
=[1/(sinxcosx)]-2sinxcosx + 2sinxcosx
=1/(sinxcosx)
=2/sin2x
化简{sin(π+x)}/1+cos(3π-x)根号下(tanx-sinx)/(tanx+sinx)
化简sin^x*tanx+cos^x*1/tanx+2sinx*cosx
[tanx+(1/tanx)]cos^x
提问数学难题求证:sin^2x*tanx+cos^2x/tanx+2sinx*cosx=tanx+1/tanx
证明1-2sinxcosx/cos^2x-sin^2x=1-tanx/1+tanx
证明:(1+2sinXcosX)/(sin^2X-cos^2X)=(tanX+1)/(tanX-1)
求证1+2sinxcosx/cos^2x-sin^2x=1+tanx/1-tanx
求证(1-2sinxcosx)/(cos^2x-sin^2x)=(1-tanx)/(1+tanx)SOS!
(cos^2x-sin^2x)/(1-2sinxcosx)=(1+tanx)/(1-tanx)证明题
求证:(1-2sinxcosx)/(cos^2x-sin^2x)=(1-tanx)/(1+tanx)
1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证
求证(1-2sinxcosx)/(cos²x-sin²x)=(1-tanx)/(1+tanx)
若tanx/tanx-1=-1 求sin(π/2+x)cos(3π/2-x)
tanx+cotx=(tanx+1)/tanx这个没问题撒那么tanx+cotx=(sin²x+cos²x)/sinxcosx也对撒?那么(tanx+1)/tanx=(sin²x+cos²x)/sinxcosx?怎么感觉不对、、、
cos x/sin x+sin x/(1+cos x) 化简.
(tanx+1/tanx)cos^2 x等于
(tanx+1/tanx)cos^2 x等于
sin^2xtanx+cos^2x/tanx+2sinxcosx-(1+cosx/sinxcosx)化简