x→∞ lim(5n/2)sin(2π/n)

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x→∞lim(5n/2)sin(2π/n)x→∞lim(5n/2)sin(2π/n)x→∞lim(5n/2)sin(2π/n)是n→∞则2π/n→0令a=2π/n则5n/2=5π/a所以原式=lim(

x→∞ lim(5n/2)sin(2π/n)
x→∞ lim(5n/2)sin(2π/n)

x→∞ lim(5n/2)sin(2π/n)
是n→∞
则2π/n→0
令a=2π/n
则5n/2=5π/a
所以原式=lim(a→0)5π*sina/a=5π

lim(x→∞) (5n/2)sin(2π/n)
=lim(x→∞) (5n/2)(2π/n)
=5π