[1+cos2X+sin^2x]/sinx 怎么化简?

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[1+cos2X+sin^2x]/sinx怎么化简?[1+cos2X+sin^2x]/sinx怎么化简?[1+cos2X+sin^2x]/sinx怎么化简?cos2x=(cosx)^2-(sinx)^

[1+cos2X+sin^2x]/sinx 怎么化简?
[1+cos2X+sin^2x]/sinx 怎么化简?

[1+cos2X+sin^2x]/sinx 怎么化简?
cos2x = (cosx)^2 -(sinx)^2 =1-2(sinx)^2
带入得到2-(sinx)^2/sinx = 2/sinx - sinx