设x^2+y^2=4,求dy/dx
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设x^2+y^2=4,求dy/dx设x^2+y^2=4,求dy/dx设x^2+y^2=4,求dy/dxx²+y²=4两边分别对x求导得:2x+2yy''=02yy''=-2xy''=-x
设x^2+y^2=4,求dy/dx
设x^2+y^2=4,求dy/dx
设x^2+y^2=4,求dy/dx
x²+y²=4
两边分别对x求导得:
2x+2yy'=0
2yy'=-2x
y'=-x/y
所以:dy/dx=y'=-x/y
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