若xx+2x+yy-8y+17=0,求x的y次幂的值.
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若xx+2x+yy-8y+17=0,求x的y次幂的值.若xx+2x+yy-8y+17=0,求x的y次幂的值.若xx+2x+yy-8y+17=0,求x的y次幂的值.即(x²+2x+1)+(y&
若xx+2x+yy-8y+17=0,求x的y次幂的值.
若xx+2x+yy-8y+17=0,求x的y次幂的值.
若xx+2x+yy-8y+17=0,求x的y次幂的值.
即(x²+2x+1)+(y²-8y+16)=0
(x+1)²+(y-4)²=0
所以x+1=y-4=0
x=-1,y=4
所以原式=(-1)^4=1
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