log2(x+1)＜-1 和 -log2【-（x+1）】＜-1 如何解得x的范围

|[log2(x)]^2-3log2(x)+1| log2(x+1)>log2(3-x) log2 (x+1)+log2 x=log6 不等式log2 (x+1) log2(2X-1) log2(x²+1) log2(x-1) log2(x)=-1 log2(x+1) log2(x-1) log2(x-1) log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 log2(x+1)＜-1 和 -log2【-（x+1）】＜-1 如何解得x的范围 .log2^(x+1/x+6) 画出y=log2底|x|+1和y=log2底|x+1|的图像 [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 log2(x-1)-log2(x+1)的定义域与值域 不等式|log2^x-1|不等式|（log2^x）-1|