已知x^2-5x-2005=0,求代数式[(x-2)^4+(x-1)^2-1]/[(x-1)(x-2)]

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已知x^2-5x-2005=0,求代数式[(x-2)^4+(x-1)^2-1]/[(x-1)(x-2)]已知x^2-5x-2005=0,求代数式[(x-2)^4+(x-1)^2-1]/[(x-1)(x

已知x^2-5x-2005=0,求代数式[(x-2)^4+(x-1)^2-1]/[(x-1)(x-2)]
已知x^2-5x-2005=0,求代数式[(x-2)^4+(x-1)^2-1]/[(x-1)(x-2)]

已知x^2-5x-2005=0,求代数式[(x-2)^4+(x-1)^2-1]/[(x-1)(x-2)]
x^2-5x-2005=0,
x^2-5x-2005=0,
x^2=5x+2005
代数式[(x-2)^4+(x-1)^2-1]/[(x-1)(x-2)]
=[(x-2)^4+(x-1+1)(x-1-1)]/[(x-1)(x-2)]
=(x-2)[(x-2)^3+x]/[(x-1)(x-2)]
=[x^3-6x^2+12x-8+x]/(x-1)
=[x*(5x+2005)-6*(5x+2005)+13x-8]/(x-1)
=[5x^2+2005x-30x+6*2005+13x-8]/(x-1)
=[5(5x+2005)+1988x+12022]/(x-1)
=[25x+10025+1988x+12022]/(x-1)
=(2013x+22047)/(x-1)
题目是否有误,计算太复杂了.

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