sn=2*3^n,求an
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/08 05:41:37
sn=2*3^n,求ansn=2*3^n,求ansn=2*3^n,求anSn=2*3^n=3*2*3^(n-1)Sn-1=2*3^(n-1)an=Sn-Sn-1=2*2*3^(n-1)=4*3^(n-
sn=2*3^n,求an
sn=2*3^n,求an
sn=2*3^n,求an
Sn = 2 * 3^n = 3 * 2 * 3^ (n-1)
Sn-1 = 2 * 3^(n-1)
an= Sn -Sn-1 = 2 * 2* 3^ (n-1)=4*3^(n-1)
an=4*3^(n-1)
sn=2*3^n,求an
an=n*2^n,求Sn
an=2^n+n,求Sn
已知an=(2n+1)*3^n,求Sn
数列{an}前n项和为Sn,且2Sn+1=3an,求an及Sn
数列an满足a1=1/3,Sn=n(2n-1)an,求an
已知数列AN的前N项和SN,SN=2N^2+3n+2,求an
Sn为等比数列{an}前n项和,an=(2n-1)*3的n次方,求Sn
等差数列{an}前n项和为Sn=3n-2n^2,求an
数列an,an=(2n-1)+1/【3n(n+1)】,求Sn
数列{an},中,a1=1/3,设Sn为数列{an}的前n项和,Sn=n(2n-1)an 求Sn
an=n+2^(n-1),求sn an=3/n(n+1),求sn an=1an=n+2^(n-1),求sn an=3/n(n+1),求sn an=1/(2n+1)(2n-1)求sn
a1=1/2,Sn=n^2an-n(n-1),求Sn和an
已知数列前n项和为Sn,且Sn=-2n+3,求an及Sn
Sn为数列{an}前n项和,(2n-1)Sn+1-(2n+1)Sn=-4n-3 ,求{an}通项公式
已知数列{an}满足:a1=3,an=Sn-1+2n,求数列an及sn
一道关于数列 已知数列{An}的前n项和为Sn,Sn=3+2An,求An
数列an的前n项和为Sn 且Sn=1-2/3an 求an的极限