化简cot(-α-π)·sin(-π-α)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 11:38:16
化简cot(-α-π)·sin(-π-α)化简cot(-α-π)·sin(-π-α)化简cot(-α-π)·sin(-π-α)cot(-α-π)·sin(-π-α)=cos(-π-α)=cos(π+α
化简cot(-α-π)·sin(-π-α)
化简cot(-α-π)·sin(-π-α)
化简cot(-α-π)·sin(-π-α)
cot(-α-π)·sin(-π-α)
=cos(-π-α)
=cos(π+α)
=-cosα
cot(-α-π)·sin(-π-α)
=-cotasina
=-cosa
cot(-α-π)·sin(-π-α)
=-cota*sina
=-cosa/sina*sina
=-cosa
化简cot(-α-π)·sin(-π-α)
化简:[sin(2004π-α)cos(α-2005π)/cot(2003π-α)sin(α+3π)]+sin(α-π)
化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α)
sin(π+α)=1/2,求sin(2π-α)-cot(α-π)cosα
化简(cos^2α-sin^2β)/(sin^2α*sin^2β)-cot^2αcot^2β
化简(cosα^2-sinβ^2)/(sinα^2sinβ^2)-cotα^2cotβ^2
化简sinαcosα(tanα+cotα)
化简 sinαcosα(tanα+cotα)
化简:sinα ×cosα(tanα+cotα)
(cot^2)α((tan^2) α-(sin^2) α) 化简
化简cosα+cotα/1+sinα
化简tan(α-π)cos(α-3π)/tan(3π+α)cot(-π-α)sin(-α)
化简[sin(π-α)tan(5π/2+α)]/[cos(2π-α)cot(π/2-α)]分后给
化简(sin^4α*cot^2α)-1
化简:sin(3π +a ) cot (- π +a )=?
化简:(cos^2α-sin^2α)/【2*cot(π/4+α)*cos^2(π/4-α)】
化简sin²(α+π)·cos(π+α)·cot(-α-2π)/tan(π+α)·cos²(-α-π)求答案
cot(π+α)=cotα