若|x+y+3|+(xy+4)`2+0 求(2xy+2y+3)-4[xy+x]-4(y-3xy)
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若|x+y+3|+(xy+4)`2+0求(2xy+2y+3)-4[xy+x]-4(y-3xy)若|x+y+3|+(xy+4)`2+0求(2xy+2y+3)-4[xy+x]-4(y-3xy)若|x+y+
若|x+y+3|+(xy+4)`2+0 求(2xy+2y+3)-4[xy+x]-4(y-3xy)
若|x+y+3|+(xy+4)`2+0 求(2xy+2y+3)-4[xy+x]-4(y-3xy)
若|x+y+3|+(xy+4)`2+0 求(2xy+2y+3)-4[xy+x]-4(y-3xy)
|x+y+3|+(xy+4)`2=0
x+y+3=0
xy+4=0 x=-4,y=1
x=1,y=-4
(2xy+2y+3)-4[xy+x]-4(y-3xy)
=3-4x-2y+10xy
=-2x-39
-41或 -31
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